CHAMFER
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Posted by: MTN33624 ® 05/05/2008, 17:02:30 Author Profile eMail author Edit

CAN YOU USE "C" TO CALL OUT A CHAMFER? IF SO, DO U NEED TO ADD THE DEGREES. EXAMPLE: C 0.10 OR .010 X45 DEG. CHAMBER. IS THIS THE SAME.

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Re: CHAMFER
Re: CHAMFER -- MTN33624	Post Reply	Top of thread	Forum

Posted by: dadstillsurfs ® 02/16/2010, 20:57:13 Author Profile eMail author Edit

ANSI Y14.5m states that you have the option of specifying chamfers by size and angle or size and size. The real issues arise when: 1. Your feature is too small to effectively inspect the angle. 2. Your angle is so tight (small angle deviation). 3. The tolerances describing the features are skewed. - very typical in size and angle. This usually shows up once the parts are made, accepted by QA and are on the floor. Probably the worst case scenario. IMHO Size by size are very easy to define, usually easy to inpect and the tolerances match. Size by angle are common among short-run prototype shops that dimension to "suit the machinist".

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Re: CHAMFER
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Posted by: jboggs ® 05/11/2008, 18:54:34 Author Profile eMail author Edit

It is not uncommon on Japanese drawings to see "C1" or "R2" for a 1mm chamfer or 2mm fillet radius. I don't know about the strict requirements of various standards, but my own rule is that drawing notations should convey the required information with the least chance of misunderstanding in the least space. If "1 x 45 deg chamfer" is what you mean "C1" works for me, but if you mean "1 x 30 deg" you better say so. Just my opinion.

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Re: CHAMFER
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Posted by: Kelly Bramble ® 05/05/2008, 17:10:33 Author Profile eMail author Edit

You can indicate Chamfers by: Distance X Angle Distance by Distance or dimension directly from a reference surface. Typically one will see the words "Chamfer" next the the chamfer dimenional callout, however the words are not actually required.

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Re: Re: CHAMFER -- Kelly Bramble	Post Reply	Top of thread	Forum

Posted by: saravananpg ® 05/15/2008, 05:56:15 Author Profile eMail author Edit

Normally chamfer indicated by distance X angele.i.e 2x45°.here 2 mm is required distance with 45°. Thanks, Saravanan P.G

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