Shaft Couplings Design Equation and Calculator

Solid Rigid Shaft to Shaft Couplings Design Equations and Calculator

Solid Rigid Couplings Design Equations and Calculator

Preview: Solid Rigid Couplings Design Calculator

The a shaft to shaft solid coupling does not allow for misalignment, except axial, but enables the extension from one piece of equipment to another. In its simplest form, the rigid coupling is nothing more than a piece of bar stock bored to receive two shafts, as shown above. Its torque-handling capacity is limited only by the strength of the material used to make the connection. The coupling is installed on one shaft before the equipment is lined up, and the mating equipment is brought into position without much chance of accurate alignment when the equipment is bolted into position.

The maximum shear stress occurs at the outer radius of the coupling and at the interface of the two bores. This stress can be derived from the torsion formula:

τmax = T Do / 2 J

Where J, the polar second moment of intertia is:

J = π / 32 ( D4o - D4i )

The coupling must be sized so that, typically, the stress does not exceed 10 percent of the ultimate tensile strength of the material.

Other factors to consider are the length of engagement into the coupling. The shear stress over the keyway must not exceed the allowable shear stress as given above. The centroidal radius is:

Rc = 0.5 * ( Do / 2 + Di / 2 + h )

The centroid of the bearing area is at radius (Di + h) / 2. If the transmitted torque is T, then the compressive force F is 2 T / (Di + h). The bearing stress σb is:

σb = F / A = 4 T / ( w L (Di + h) )

The allowable compressive stress from distortion energy theory of failure is σall = τall / 0.577. Combining this equation σb with gives:

τall = [ 0.577 ( 4 ) T ] / [ w L (Di + h) ]

Next, the length of key stock, for keyed shafts, must be examined to keep its shear loading from exceeding the allowable shear stress. Referring to the equation for σb , we note that the shear force is:

F = T / τ /2) = 2 T / Di Therefore the average shear stress is

τ = F / A = ( 2 T ) / ( w L Di )

Rigid couplings

Shaft Key

 

Both keys must be checked, although experience has shown that small diameter shafts are more prone to failure of the key and keyway when these precautions are not followed because of their normally smaller key width and length of engagement.

Maximum Allowable Shear Stress
Material
Stress, psi
Aluminum
4000
Cast Iron
4500
Ductile Iron
6000
Brass
3500
Powered Iron

4000

Steel
8000

Where:

T = Torque, lb-in
Do = Diameter Outer, in
Di = Diameter inner, in
J = Polar Second Moment of Inertia, in3
Rc= Centroidal radius or distance, in
F = Compressive Force, lbf
A = Cross Sectional Area (in2)
w = Width, in
L = Length, in
h = Keyway height, in
τall = Compresive Shear Stress, psi
τ = Shear Stress, psi

References:

ISO R773, Rectangular or Square Parallel Keys and Their Corresponding Keyways, 1969.
JISB 1301, Bore and Keyway Tolerances.

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