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| Yet another I-beam question. | |||
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| Posted by: Paul Cotter ® 04/23/2008, 10:30:57 Author Profile eMail author Edit |
Sorry that this question is so similar to others. In a family home I need to span 14 foot to provide support for bedrooms above. The roof will not be supported by the beam but the attic will. The joists resting on the beam will extend 12 foot on both sides of the beam. The construction above the beam is 'normal'.
Many thanks Modified by Paul Cotter at Wed, Apr 23, 2008, 10:34:36 |
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| : Yet another I-beam question. | |||
| : Yet another I-beam question. -- Paul Cotter | Post Reply | Top of thread | Forum |
| Posted by: randykimball ® 04/23/2008, 22:12:26 Author Profile eMail author Edit |
http://www.engineersedge.com/beam_bending/beam_bending1.htm
..is a good place to begin. The worst suggestion of your lifetime may be the catalyst to the grandest idea of the century, never let suggestions go unsaid nor fail to listen to them. |
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| : : Yet another I-beam question. -- randykimball | Post Reply | Top of thread | Forum |
| Posted by: Paul Cotter ® 04/24/2008, 08:32:10 Author Profile eMail author Edit |
Perfect - thank you. It still took me a while. The last engineering I did was at Imperial College 35 years ago. So just to help any others that google their way here. Deflection = 5/384 * W * L^3 / ( E * I) for a 'normal' straight I-Beam supported at its ends and uniformly loaded. Using Imperial measurements we have. W = Load in pounds. L = length in inches. E (Young's modulus or modulus of elasticity) for plain old mild steel is in the range 29,000,000 to 30,000,000 pounds per square inch. I = (second) moment of inertia for the beam. I found this table at a site called efunda. http://128.242.106.218/math/areas/RolledSteelBeamsW.cfm And no - the beam is inadequate. The deflection is beyond the limits acceptable under code here in Ontario.
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