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| Sheet Metal Design |  |  | |
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| Posted by: krazy_aljoe ® 05/06/2008, 23:23:28 Author Profile eMail author Edit |
Dear All, I am currently designing a sheet metal frame to hold an LCD and Elastomeric Connector (zebra rubber). (In my attachment, the elastomeric connector is the one with zigzag lines and the white area is the LCD.) The assembly is secured in the PCB by bending the legs of the frame at the back of the PCB (partially visible in my attached file). My concern is that, will the frame be able to withstand the force (15-20N) exerted by the compressed elastomeric connector? The frame has a weak area (encircled yellow in the attached file). The thickness of the frame is 0.4mm and the material is SUS 301/SUS 304.
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| Posted by: Marky ® 05/07/2008, 07:39:25 Author Profile eMail author Edit |
Hi and welcome. Looks a little weak there. Couple of questions...Is this a touchscreen?...I was fixing a design similar to this. The cover much like your design would compress against the screen too much and crack it everytime a operator would touch it. Could you make a prototype to try? It looks like even your software could flag any problem areas. And finally....Are there any worrys about EMI/RFI? |
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| Posted by: krazy_aljoe ® 05/07/2008, 21:06:16 Author Profile eMail author Edit |
Hi Marky. Thanks for the reply. This is not a touchscreen. We want to make a prototype out of it but I want to fix problems first. Unfortunately, my design software is not capable of analyzing critical areas. Do you think increasing the thickness will help? That area is unavoidable because connectors of an EL Lamp must pass on that area. For EMI/RFI, I believe there are no worries on that. |
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| Posted by: Kelly Bramble ® 05/07/2008, 20:47:44 Author Profile eMail author Edit |
Let's see, 1 Newton = 0.22481 lbf, so 20 Newtons equal 4.5 lbs of force.. Are your units in MM or inches? Modified by Kelly Bramble at Wed, May 07, 2008, 20:48:21 |
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| Posted by: krazy_aljoe ® 05/07/2008, 21:38:35 Author Profile eMail author Edit |
Hi Kelly.. Actually, I got the formula for the force exerted by a compressed elastomeric connector from a manufacturer of this kind. I recalculated and the value I got now is 12N (for two connectors combined). If the force exerted is at 12N, will the Frame still withstand the stress? |
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| Posted by: Kelly Bramble ® 05/08/2008, 14:39:23 Author Profile eMail author Edit |
I take it the entire loading is 12N? You should determine the loading in force per area then look at your material specification, etc. For anybody on this engineering forum to gove you a conclusive answer we would need details. Most of us prefer to work in concepts btw. Running the math is not my favorite way to spend the day.. |
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