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Calculating work done on a hydraulic pump
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Posted by: DavidPerth ®

11/20/2009, 19:34:18

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Hi, I have to calculate the work done on a simple linear hydraulic pump and need some guidance.

The pump circulates fluid in a closed circuit, as part of a test system. The fluid discharge is routed back to the inlet via a pressure reducing system.

The actuator of the pump consists of a flywheel driven by a constant velocity electric drive. A fibre rope connects the pump rod end to a boss on the flywheel, via a deflection sheave. The idea is that this arrangement reciprocates the pump with a sinusoidal velocity profile. Note the actuator can only pull on the rod, it cannot push it to get the piston to return (rope only works in tension). To do this, we use hydraulic means (i.e. we configure the pump's inlet pressure to be sufficient to force the piston to return). The rope remains in tension on both the extension and retraction of the pump, but is much higher on the extension as this is the pump discharge stroke (pulling against high pressure). The actuator essentially brakes the return of the piston during the inlet stroke.

My goal is to calculate the efficiency of the pump. To do this, I need to calculate the work done by the actuator on the pump. I measure the tension applied to the rod end and the displacement of the piston, so my current solution to this is to integrate force with respect to displacement. However, this means the actuator is doing negative work during the pump's inlet stroke (force applied is in opposite direction to displacement). I think this is correct, as the pump is then doing work on the actuator and not vice versa, so the actuator recovers some of the work done during the discharge stroke. I would welcome a second opinion though. Maybe the work done on the pump is only that during the discharge stroke. Hmmm...confused!








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: Calculating work done on a hydraulic pump
: Calculating work done on a hydraulic pump -- DavidPerth Post Reply Top of thread Engineering Forum
Posted by: zekeman ®

11/20/2009, 22:45:08

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Yes, force in the same drection as the rod motion is work on the pump and obviously if the rod is going opposite of the force vector it is doing the work.







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: Calculating work done on a hydraulic pump
: Calculating work done on a hydraulic pump -- DavidPerth Post Reply Top of thread Engineering Forum
Posted by: zekeman ®

11/20/2009, 22:44:40

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Yes, force in the same drection as the rod motion is work on the pump and obviously if the rod is going opposite of the force vector it is doing the work.







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