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Shaft Diameter Calculations
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Posted by: mikee122

04/27/2007, 16:04:08

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I am looking for either a simple formula or simplified formulas to determine the min. shaft diameter.

For example I know the torque vaule, the type of loading (repeated torsion), the length of the shaft with the maximum amount of Angle of twist.

T=50,000
Loading = 4
Shaft length = 20 foot
Max AOT = 10 degrees

I plan on using 4140 Steel, normalized (TS 148,000 psi, YS 95,000 psi)

In the event there are several formulas please list in a logical order








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Re: Shaft Diameter Calculations
Re: Shaft Diameter Calculations -- mikee122 Post Reply Top of thread Forum
Posted by: bobthedog

04/29/2007, 12:46:41

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Hey just wondered are u doing the ics engineering course

To proceed mike Torque is measured in kjoules 1000 joules equal one killer joule

Loading 4 what does that mean 4 what

Also is with that steel 4140 TS AND YS is YS YIELD STRENGTH WHAT IS TS ???

Got about 4 equations for u but wanted to find that out ok cheers.





DONT GIVE UP THE FAITH


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Re: Re: Shaft Diameter Calculations
Re: Re: Shaft Diameter Calculations -- bobthedog Post Reply Top of thread Forum
Posted by: bobthedog

04/29/2007, 13:03:59

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Torque is also measured in oz aswell sorry onces


Can u help with this

how to work out 1/16 of an inch and 3/16 of an inch on a calculator etc how its put onto the calculator and to do

Also m2 is meteres squared but m 3 is meters cubed where on the calculator is meters cubed button thanks





DONT GIVE UP THE FAITH


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Re: Shaft Diameter Calculations
Re: Shaft Diameter Calculations -- mikee122 Post Reply Top of thread Forum
Posted by: materialboy

04/28/2007, 07:21:34

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The diameter is with in ur values.

Torque = radius * perpendicular force F

where Loading gets to be the perpendicular force because it is the shaft.

What value is loading of 4 ???

r = Torque/ Force F








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Re: Re: Shaft Diameter Calculations
Re: Re: Shaft Diameter Calculations -- materialboy Post Reply Top of thread Forum
Posted by: mikee122

04/28/2007, 11:44:12

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Could you please clarify. I am trying to determine the diameter. I don't have a diameter value

In r=Torque/Force would not the Torque be equal to the perpendicular loading?

I am referencing a chart that states that shows the loading value based on the type of loading.

Manner of loading Design factor Design shear stress
T sub d= s sub y/2N ________________________________________________________________
Static or steady torsion 2 T sub d= s sub y/4
repeated torsion 4 T sub d= s sub y/8
torsion impact or shock 6 T sub d= s sub y/12

T=50,000
Loading = 4
Shaft length = 20 foot
Max AOT = 10 degrees

I did make a minor change to the material I would like to use.

I plan on using 4140 Steel,OQT 700 (US 231 ksi/1593 MPa,
YS 212 ksi/1462 MPa)








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Re: Re: Re: Shaft Diameter Calculations
Re: Re: Re: Shaft Diameter Calculations -- mikee122 Post Reply Top of thread Forum
Posted by: materialboy

04/29/2007, 11:43:49

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How far I understand, Torque = Radius*Prependicular Force
So, in your question, Force will be created by perpendicular loading.
Hence, if your loading is acting prependiculary than yes it will replace perpendicular force.

Manner of loading Design factor Design shear stress
T sub d= s sub y/2N ???_________________________

What does your [s sub y/2N] stands for ???

_____________________________________








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Re: Re: Re: Re: Shaft Diameter Calculations
Re: Re: Re: Re: Shaft Diameter Calculations -- materialboy Post Reply Top of thread Forum
Posted by: mikee122

04/29/2007, 15:58:43

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I am doing a strength of materials course fir Mech. Design.

Our text book is Strength of Materials, 4th edition by Robert L Mott

The table is
Manner of loading | Design factor | Design shear stress
| | T sub d= s sub y/2N
______________________________________________________________
Static or steady | 2 | T sub d= s sub y/4
torsion | |
_____________________________________________________________
repeated torsion | 4 | T sub d= s sub y/8
_____________________________________________________________
torsion impact | 6 | T sub d= s sub y/12
shock
_____________________________________________________________

T=50,000 lb-ft
Loading = 4
Shaft length = 20 foot
Max Angle Of Twist = 10 degrees

I plan on using 4140 Steel,OQT 700 (US 231 ksi/1593 MPa,
YS 212 ksi/1462 MPa)
US = Ultimate Strength , YS = Yield Strength

T sub d= s sub y/2N is the formula for Design shear stress.


In the formula (Torque = Radius*Prependicular Force)

Would Radius=50,000lb-ft/4(the design factor of 4)???








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Re: Re: Re: Re: Re: Shaft Diameter Calculations
Re: Re: Re: Re: Re: Shaft Diameter Calculations -- mikee122 Post Reply Top of thread Forum
Posted by: materialboy

04/30/2007, 06:56:12

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Well if you understand the meaning of MPa and stress, u won't ask on the prependicular.

Ur answer is with in the statement u have just written.








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