Linear force required

[FONT=Times New Roman][SIZE=3][COLOR=#000000] [/COLOR][/SIZE][/FONT][COLOR=black][FONT="Arial"]Hi, [/FONT][/COLOR]
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[FONT=Times New Roman][SIZE=3][COLOR=#000000] [/COLOR][/SIZE][/FONT][COLOR=black][FONT="Arial"]I have a question about calculating the linear force required to push a crane hook, and its attached block arrangement, to a certain angle in order to test our inclinometer trip settings. The total weight of the hook and block arrangement is estimated at 9,500kg and it needs to move to an angle of 6 degrees (worked out as needing to move a horizontal distance of 0.7m). [/FONT][/COLOR]
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[FONT=Times New Roman][SIZE=3][COLOR=#000000] [/COLOR][/SIZE][/FONT][COLOR=black][FONT="Arial"]Looking into a new method for testing through using a linear actuator to push the hook longitudinally and transversely. What linear force would be required to push this hanging weight? Or how would I go about calculating this?[/FONT][/COLOR]
[FONT=Times New Roman][SIZE=3][COLOR=#000000] [/COLOR][/SIZE][/FONT][COLOR=black][FONT="Arial"] [/FONT][/COLOR]
[FONT=Times New Roman][SIZE=3][COLOR=#000000] [/COLOR][/SIZE][/FONT][COLOR=black][FONT="Arial"]I am sure it is fairly straightforward but any help would be appreciated![/FONT][/COLOR]
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Wouldn't this turn into a tangential force, rather than linear?

I need a figure for the force the linear actuator can push, I have done the following:

F = ma +mg*Sin(theta)

Is this correct? Comes out around 10KN which seems reasonable given the mass is hanging?