Guys,
I make a bar to have clearance fit into a slot. The bar is X+0/-.0010" (eg: 1.0000 +0/-.0010" , which give a tolerance of .0010"). Now, the slot size is either (a) X+.0010/+.0002" (tol= .0008") or (b) X+.0010/+.0005" (tol=.0005").
Q: which tolerance fit best, easier machining process and cost effective?TQ