ONE THING MAKES ME STILL CONFUSING IF THE LIFT HEIGHT OF THE SCISSOR IS 3 METERS OR 5 METERS HOW MANY NOS OF CYLINDERS WILL BE NEEDED TO OPEN THE HYDRAULIC SCISSOR LIFT OF CAPACITY 500 KGS ?????
AND HOW THIS EQUATION F (FORCE ON THE CENTRE PIN) = (W + wf/2) / tan phi will play the role in this juncture ???
W = Weight of the load.
wf/2 = Weight of the frame.
Phi = Interior angle between horizontal and the arm.
kindly advise.
with b'rgds,
b.sandip
