• 02-14-2012, 12:03 PM
esuhartanto
How do I calculate the minimum pad eye plate thickness needed to lift 6000 lbs Maximum Allowable Weight [ATTACH]158[/ATTACH]

Thanks,
Eli
• 02-14-2012, 06:03 PM
Kelly Bramble
Your PDF file drawing is missing details...
• 02-14-2012, 06:47 PM
esuhartanto
missing details like the you cant see the drawing?
• 02-15-2012, 03:25 AM
Hans
First, you must calculate the thickness of the tensile condition. Second, the right and left side is bent. Third, you need to check the hole for pressure forming.

[URL=http://fotoo.pl/show.php/91494_en-edge.jpg.html][IMG]http://fotoo.pl//out.php/t91494_en-edge.jpg[/IMG][/URL]

Quick analysis of the case. I hope you understand. Of course, after all, an analytical method provides only rough results. The exact result will provide only the finite element method (FEM).

I greet.
• 02-15-2012, 06:57 AM
jboggs
I know this isn't the exact loading situation, but I would just look at the pure tension capacity of the thinnest cross section. Then I would double it, then I would double it again, and probably even again, depending on the application.

My philosophy in very few words: Steel is cheap. Accidents aren't.
• 02-15-2012, 09:37 AM
PinkertonD
:D ...and I thought I was a nervous Nelly. :D I would have stopped at the second "double." :)
• 02-15-2012, 10:55 AM
Hans
[QUOTE=jboggs;2170]
My philosophy in very few words: Steel is cheap. Accidents aren't.[/QUOTE]

Well said :)
• 02-16-2012, 06:48 AM
Android
[QUOTE=jboggs;2170]I know this isn't the exact loading situation, but I would just look at the pure tension capacity of the thinnest cross section. Then I would double it, then I would double it again, and probably even again, depending on the application.

My philosophy in very few words: Steel is cheap. Accidents aren't.[/QUOTE]

Whilst making the plates thicker would be a good idea......better put a slot through the base plate and welding from both sides then you have 4 welds to break and not just 2.

My 2 penneth