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Thread: Motor Torque Requirement

  1. #1
    Associate Engineer
    Join Date
    Jun 2013
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    2

    Motor Torque Requirement

    Can someone please confirm my calculation.


    I am designing an indexing toolmount out of a rectangular frame that has a shaft going through the center of each end of the frame. The shaft is mounted on bearings on each end. The tool is well balanced and total mass including the shaft is 600lbs. The tool width is 40 inches. I want to be able to rotate the tool to 15 RPM in 5 seconds. With friction out of the equation, the question is will a servo motor with a 14 Nm output torque rated at 5000 rpm attached to a 4:1 worm gear work?

    Mass = 600lbs = 272.16kg
    Distance to center = 20 in = .508m
    RPM = 15
    Time (t) = 5 sec

    Here are formulas I am using.

    Find central axis moment of inertia = 1/2 *M( R * R)
    I = 1/2 * 272.16 * .258
    I = 35.11kg m2

    Convert RPM to radians/s = 2Pi(RPM/60)
    Radians/s = 1.57 rad/s

    Find Angular Acceleration
    a = acceleration, V1 = Initial velocity, V2 = Final velocity
    a = (V2-V1)/t
    a = (1.57 - 0)/t
    a = .314 rad/s/s or round up in degrees to 18 deg/s/s

    Find Torque
    Torque = i * a
    Torque = 35.11 * .314
    Torque = 11.02 Nm

    So using a worm gear would be more than enough since my the minimum Torque requirement is 11.02 Nm?

  2. #2
    Principle Engineer Cragyon's Avatar
    Join Date
    Feb 2013
    Location
    Newark, NJ
    Posts
    196
    Well, your math seems right so I agree....


    Mass Moment of Inertia

    Gear Drive Systems

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