# Thread: 160 in the formula of weight calculation of s.steel blank

1. ## 160 in the formula of weight calculation of s.steel blank

Pls. let me know that how the 160 (or) 160000 is used to find the weight of s.steel blank?.

Thx.  Reply With Quote

2. Originally Posted by pakirmohd Pls. let me know that how the 160 (or) 160000 is used to find the weight of s.steel blank?.

Thx.

weight = Height x Width x Length x Density

Density = Mass/Volume

Where:

Height = in. or mm
Width = in. or mm
Length = in. or mm
Density = lbs/in^3 or Kg/mm^3 or what ever units makes you happy...  Reply With Quote

3. Thx.
I saw a methode to find weight of steel blank.
This is the formula: Dia x Dia x Thick/160
How did 160 come?  Reply With Quote

4. Originally Posted by pakirmohd Thx.
I saw a methode to find weight of steel blank.
This is the formula: Dia x Dia x Thick/160
How did 160 come?
I do not know what that equation is..
Again, weight is equal to:

weight = Volume x Density  Reply With Quote

5. Pakirmohd, what units do you work in for length and weight?

The equation for weight of a cylinder (i.e. circular blank) is:
Weight = (3.14*D*D/4)*(thickness)*(density)

The 160 probably comes from simplification of:
a) pi (3.14)
b) 4
c) the density of steel
d) any unit conversions.  Reply With Quote

6. Interesting. Thx.  Reply With Quote

7. I do not believe that the given equation can be assumed to be a valid general equation for determining tubing weights; because the substitution of D*d to replace "(D^2 - d^2)" in a the standard equation: (D^2 - d^2) * pi/4 * t (thickness of the plate) for the volume of metal in a cylinder is not valid.

The only way I can see the above equation being valid is if it is for a specific O.D. I.D. ratio tube; where, for example, d = D/2 and the 2 is one of the factors included in the 160 divisor value.

The D*D in above equation is only the equivalent of D^2 in the standard formula: D^2 * pi/4 * t for the volume of metal in a solid round bar.

I also performed trials using the standard density for a number of metals in the equation and none resulted in the 160 divisor value.  Reply With Quote

8. The equation I presented is only valid for a solid steel blank, see attached picture.

Pakirmohd, what units are you using for this equation? Meters? centimeters? millimeters? Inches? And for weight... Pounds? kilograms?

Thanks,
Will   Reply With Quote

9. Dear Will,
It's mm.  Reply With Quote

10. Pakirmohd, please forgive my confusion, while I realize the correct geometrical term for a solid cylindrical shape is a "cylinder", in the industries in which I have worked this term is principally utilized to indicate a tubular item and "round bar" is the term used to identify a solid cylinder of material.

1/160 = 0.0063 as a multiplier and I cannot find a single material units of density that will convert this to the generally acceptable density value of .283 lb/ft^3 or 489 lb/ft^3 for basic steel.

In addition to Will1234's request for the units, can you also attach a copy of the original document giving this equation?  Reply With Quote

11. It's great answer with perfect calculation.  Reply With Quote

#### Posting Permissions

• You may not post new threads
• You may not post replies
• You may not post attachments
• You may not edit your posts
•