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Thread: Conveyor belt Motor Power Calculation

  1. #1
    Associate Engineer
    Join Date
    Feb 2017

    Conveyor belt Motor Power Calculation

    Hello Designer,

    I need to know if my calculation is correct or not for my belt conveyor used to transport tobacco product.

    Belt length = 34m
    Belt width = 1000 mm
    load due to belt =1.8kg/m2
    idler spacing = 0.51 m
    load due to convoyed material is 15 Kg/m ...
    H= 1.2m
    i used this formula:
    Tb = 1.37*f*L*g*[2*mi+ (2*mb + mm)*cos (δ)] + (H*g*mm)

    Tb is in Newton.

    f = Coefficient of friction
    L = Conveyor length in meters. Conveyor length is approximately half of the total belt length. =34 m
    g = Acceleration due to gravity = 9.81 m/sec2
    mi = Load due to the idlers in Kg/m. = 117.6
    mb = Load due to belt in Kg/m. =1.8 kg/m
    mm = Load due to the conveyed materials in Kg/m. = 15 kg/m
    δ = Inclination angle of the conveyor in Degree. zero
    H = vertical height of the conveyor in meters. 1.2 m

    • Load due to idlers (mi): This can be calculated as below:

    mi = (mass of a set of idlers) / (idlers spacing)

  2. #2
    Associate Engineer
    Join Date
    Oct 2017
    Nice to read you forum. For a long time I was eager to know the functioning of conveyor belt, mechanism and force that drive the belt. The equation is self explanatory. I work for a website "" that deals in conveyor belt business.

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