I need to know if my calculation is correct or not for my belt conveyor used to transport tobacco product.
Belt length = 34m
Belt width = 1000 mm
load due to belt =1.8kg/m2
idler spacing = 0.51 m
load due to convoyed material is 15 Kg/m ...
i used this formula:
Tb = 1.37*f*L*g*[2*mi+ (2*mb + mm)*cos (δ)] + (H*g*mm)
Tb is in Newton.
f = Coefficient of friction
L = Conveyor length in meters. Conveyor length is approximately half of the total belt length. =34 m
g = Acceleration due to gravity = 9.81 m/sec2
mi = Load due to the idlers in Kg/m. = 117.6
mb = Load due to belt in Kg/m. =1.8 kg/m
mm = Load due to the conveyed materials in Kg/m. = 15 kg/m
δ = Inclination angle of the conveyor in Degree. zero
H = vertical height of the conveyor in meters. 1.2 m
- Load due to idlers (mi): This can be calculated as below:
mi = (mass of a set of idlers) / (idlers spacing)
Nice to read you forum. For a long time I was eager to know the functioning of conveyor belt, mechanism and force that drive the belt. The equation is self explanatory. I work for a website "universaldelhi.org" that deals in conveyor belt business.