1. Hydraulic jack

How to calculate the wall thickness of 500 ton jack ? How to calculate the bore dia of hydraulic jack of 500 ton ? How to calculate the working pressure of 500 ton jack ? How to calculate the buckling effect of the ram of 500 ton hydraulic jack ?

Kindly make me understand in a very simple mode.

With b'rgds,
b.sandip

2. If you are thinking of making your own 500-ton hydraulic jack, I suggest you think again and go buy one. Hydraulic pressure to move 500-tons is no small feat. There are seal designs to think of, surface finishing of rams, pistons and bores, just for a start.

Working out the strength of materials is the easiest part.

But then, if it is a homework project then you should check...
http://www.engineersedge.com/enginee...Posting-Policy

3. plz send me the design and calculation of hydraulic jack????

4. Originally Posted by abhi kumar
plz send me the design and calculation of hydraulic jack????
Seriously?

5. Dear Esteemed Engineers,

I am in the process of finishing up my thesis for the final year of my mechanical engineering project and require your kind help.

I am trying to show that by using hydraulic jacks one can perform the shifting of hatch covers of a vessel efficiently without using a crane.

How do i show the calculations.

I have 4 jacks rated at 10 tons each shifting a hatch cover approximately 25 tons in weight a distance of about 300mm upwards.

Single Stroke with spring return, Manual hydraulic pump ( Jacking Method)

Already done the practical part but need to show calculations to show proof of research.

Could someone point me in the correct direction.

Very much appreciated.

6. You are in your final year of mechanical engineering and you don't know how to show calculations? It's a little late to ask. You could not have "done the practical part" without some calculations. Show them.

7. see this i hope this will help you ..

Cylinder Blind End Area (in square inches):
PI x (Cylinder Radius)2

Example: What is the area of a 6" diameter cylinder?
Diameter = 6"
Radius is 1/2 of diameter = 3"
Radius2 = 3" x 3" = 9"

π x (Cylinder Radius)2 = 3.14 x (3)2 = 3.14 x 9 = 28.26 square inches

Cylinder Rod End Area (in square inches):
Blind End Area - Rod Area
Example: What is the rod end area of a 6" diameter cylinder which has a 3" diameter rod?
Cylinder Blind End Area = 28.26 square inches
Rod Diameter = 3"
Radius is 1/2 of rod diameter = 1.5"
Radius2 = 1.5" x 1.5" = 2.25"
π x Radius2 = 3.14 x 2.25 = 7.07 square inches

Blind End Area - Rod Area = 28.26 - 7.07 = 21.19 square inches

Cylinder Output Force (in pounds):
Pressure (in PSI) x Cylinder Area
Example: What is the push force of a 6" diameter cylinder operating at 2,500 PSI?
Cylinder Blind End Area = 28.26 square inches
Pressure = 2,500 psi
Pressure x Cylinder Area = 2,500 X 28.26 = 70,650 pounds

What is the pull force of a 6" diameter cylinder with a 3" diameter rod operating at 2,500 PSI?
Cylinder Rod End Area = 21.19 square inches
Pressure = 2,500 psi

Pressure x Cylinder Area = 2,500 x 21.19 = 52,975 pounds

Fluid Pressure in PSI Required to Lift Load (in PSI):
Pounds of Force Needed ÷ Cylinder Area
Example: What pressure is needed to develop 50,000 pounds of push force from a 6" diameter cylinder?
Pounds of Force = 50,000 pounds
Cylinder Blind End Area = 28.26 square inches
Pounds of Force Needed ÷ Cylinder Area = 50,000 ÷ 28.26 = 1,769.29 PSI

What pressure is needed to develop 50,000 pounds of pull force from a 6" diameter cylinder which has a 3" diameter rod?
Pounds of Force = 50,000 pounds
Cylinder Rod End Area = 21.19 square inches

Pounds of Force Needed ÷ Cylinder Area = 50,000 ÷ 21.19 = 2,359.60 PSI

Cylinder Speed (in inches per second):
(231 x GPM) ÷ (60 x Net Cylinder Area)
Example: How fast will a 6" diameter cylinder with a 3" diameter rod extend with 15 gpm input?
GPM = 6
Net Cylinder Area = 28.26 square inches
(231 x GPM) ÷ (60 x Net Cylinder Area) = (231 x 15) ÷ (60 x 28.26) = 2.04 inches per second

How fast will it retract?
Net Cylinder Area = 21.19 square inches
(231 x GPM) ÷ (60 x Net Cylinder Area) = (231 x 15) ÷ (60 x 21.19) = 2.73 inches per second

GPM of Flow Needed for Cylinder Speed:
Cylinder Area x Stroke Length in Inches ÷ 231 x 60 ÷ Time in seconds for one stroke
Example: How many GPM are needed to extend a 6" diameter cylinder 8 inches in 10 seconds?
Cylinder Area = 28.26 square inches
Stroke Length = 8 inches
Time for 1 stroke = 10 seconds
Area x Length ÷ 231 x 60 ÷ Time = 28.26 x 8 ÷ 231 x 60 ÷ 10 = 5.88 gpm

If the cylinder has a 3" diameter rod, how many gpm is needed to retract 8 inches in 10 seconds?
Cylinder Area = 21.19 square inches
Stroke Length = 8 inches
Time for 1 stroke = 10 seconds

Area x Length ÷ 231 x 60 ÷ Time = 21.19 x 8 ÷ 231 x 60 ÷ 10 = 4.40 gpm

Cylinder Blind End Output (GPM):
Blind End Area ÷ Rod End Area x GPM In
Example: How many GPM come out the blind end of a 6" diameter cylinder with a 3" diameter rod when there is 15 gallons per minute put in the rod end?
Cylinder Blind End Area =28.26 square inches
Cylinder Rod End Area = 21.19 square inches
GPM Input = 15 gpm
Blind End Area ÷ Rod End Area x GPM In = 28.26 ÷ 21.19 x 15 = 20 gpm

8. jboggs. Am not a design engineer. Thats why i asked in the forum. ANyway there are others in the forum more helpful then you.

9. Originally Posted by rai0179
jboggs. Am not a design engineer. Thats why i asked in the forum. ANyway there are others in the forum more helpful then you.
I'm confused because everything you need is here in this forum thread. Where are you going to school?

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