**Related Resources: mechanics machines**

### Flywheel Mass Size Design Equation and Calculator

Preview: Flywheel Mass, Size Design Calculator

The torque-angle relationship for an engine or machine depends on the the amount of work required. The large variation that is possible between different machine designs shows that dynamic measurement or kinematic analysis is necessary to determine the torque fluctuation. It is often necessary, however, to come up with a rough estimate for preliminary design purposes or for checking the reasonableness of calculated values. For these purposes, the energy variation for a machine or internal-combustion engine can be estimated by:

Energy equation variation flywheel

U = 0.5 J ( ω^{2}_{max} - ω^{2}_{min} )

Polar-mass moment of inertia Fly Wheel. This inertia includes the flywheel inertia and the inertia of all rotating parts, referred to the flywheel speed by multiplying by the square of the ratio of the shaft speeds.

J = U / ( ω^{2}_{avg} C_{s} )

Coefficient of Speed Variation of a Flywheel

C_{s} = ( ω_{max} - ω_{min} ) / ω_{avg}

Suggested Design Values for the Coefficient of Speed Fluctuation C_{s}

Required speed uniformity |
C_{s} |

Very uniform | ≤ 0.003 |

Moderately uniform | 0.003-0.012 |

Some variation acceptable | 0.012-0.05 |

Moderate variation | 0.05-0.2 |

Large variation acceptable | ≥ 0.2 |

The coefficient of energy variation
C_{u} can be approximated for a two-stroke engine with from 1 to 8 cylinders using the
equation:

C_{u} = 7.46 / ( N_{c} + 1 )^{3}

Coefficient of energy variation for a four-stroke engine with from 1 to 16 cylinders using the two-branched equation:

C_{u} = 0.8 / ( N_{c} - 1.4 )^{1.3} - 0.015

Flywheel Weight:

W = J g / r^{2}_{a}

Cross Sectional Area of Flywheel:

A = J g / ( 2 π ρ r^{3}_{a} )

Power required :

P = T ω

Where:

J = Polar-mass moment of inertia, Ib · s^{2} · ft (N · s^{2} · m)

U = Energy Variation, difference between the flywheel energy at maximum speed and
at minimum speed, Ib · ft (J)

N_{c} = Number of cylinders

C_{u} = Coefficient of energy variation

C_{s} = Uniformity Speed Constant

K = 33 000 lb · ft · rpm/hp

ω = Rotational speed, rad/s

ω_{avg} = Average of ω_{max} and ω_{min} , rad/s

P = Power, hp (W)

g = Gravity 9.81 m/s^{2
}D = Diameter m

r_{a} = radius m

W = Mass kN

A = Cross sectional Area m^{2}

ρ = Material Density kg/m^{3}

T = Torque J ( 1 ft-lb = 1.355817948 J)

Typical Machine Power Cycle

**© Copyright 2000 - 2019, by Engineers Edge, LLC www.engineersedge.com All rights reserved
Disclaimer
| Feedback | Advertising
| Contact **

Date/Time: