Replies to this message

: Force needed to overcome a schrader valve
: Force needed to overcome a schrader valve -- spyderman	Post Reply	Top of thread	Forum

Posted by: whang ® 11/04/2008, 15:34:50 Author Profile eMail author Edit

Pressure=Force/Area If the pressure in the Canister is 1800 psi So the pressure on the piston is 1800 psi the force on the piston = pressure X area = .1963 X 1800 psi = 353.34 lb You need the force is bigger than 353.34 lb to open the valve Hope this will help you.

Post Reply Tell a Friend (must be logged in) Alert Admin About Post

Where am I? Original Top of thread

| |

: : Force needed to overcome a schrader valve
: : Force needed to overcome a schrader valve -- whang	Post Reply	Top of thread	Forum

Posted by: spyderman ® 11/04/2008, 16:00:06 Author Profile eMail author Edit

Thanks so much for your reply, That was the #'s I came up with but they did not make sense. The pin that opens the Schrader valve is attached to a piston that has a surface area of 3.9449" and is actuated with an air pig set at 100psi. Each firing depletes the tank by 10psi. Yet it is still functional at only 30psi in the tank? Would that not mean the actuation piston is only using 118.347psi to overcome the 353.34 pounds of resistance??? Thanks again!

Post Reply Tell a Friend (must be logged in) Alert Admin About Post

Where am I? Original Top of thread

| |

: : : Force needed to overcome a schrader valve
: : : Force needed to overcome a schrader valve -- spyderman	Post Reply	Top of thread	Forum

Posted by: whang ® 11/04/2008, 17:18:40 Author Profile eMail author Edit

The piston area is 3.9449 sq.in the pressure is 100 psi the force is 3.9449 x 100 psi =394.49lb so the force is overcome the 353.34lb Each firing depletes the tank by 10psi. Yet it is still functional at only 30psi in the tank? Can you give me more detail about the air pig and how it works?

Post Reply Tell a Friend (must be logged in) Alert Admin About Post

Where am I? Original Top of thread

: : : Force needed to overcome a schrader valve
: : : Force needed to overcome a schrader valve -- spyderman	Post Reply	Top of thread	Forum

Posted by: randykimball ® 11/04/2008, 17:10:30 Author Profile eMail author Edit

(3.9449 X pi) x 30 psi = 371.8, .. enough The worst suggestion of your lifetime may be the catalyst to the grandest idea of the century, never let suggestions go unsaid nor fail to listen to them.

Post Reply Tell a Friend (must be logged in) Alert Admin About Post

Where am I? Original Top of thread

| |

: : : : Force needed to overcome a schrader valve
: : : : Force needed to overcome a schrader valve -- randykimball	Post Reply	Top of thread	Forum

Posted by: spyderman ® 11/05/2008, 07:38:38 Author Profile eMail author Edit

I am not sure why the replies have given me to different #'s? As for the air pig, it is just a small accumulator with a static preload of 100-105PSI, and a solenoid opens and the Initiation pistion is forced into the Schrader valve forcing a full expulsion of the CO2 canister Thanks for the many replies Jay

Post Reply Tell a Friend (must be logged in) Alert Admin About Post

Where am I? Original Top of thread

| |

: : : : : Force needed to overcome a schrader valve
: : : : : Force needed to overcome a schrader valve -- spyderman	Post Reply	Top of thread	Forum

Posted by: whang ® 11/05/2008, 09:44:47 Author Profile eMail author Edit

Thanks for your information. Every time you open the Valve, you need to recharge the accumulator to 100-105 psi. the tank is to hold air only Air pump is used the air in the tank to charge the accumulator to boost the pressure from 30 psi to 100-105 psi So the area of a piston is 3.9449 sq.inch The pressure in the accumulator is 100-105 psi then the force which the valve gets 394.49 lb

Post Reply Tell a Friend (must be logged in) Alert Admin About Post

Where am I? Original Top of thread