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: Shear stress due to bending
: Shear stress due to bending -- mohanjatinder	Post Reply	Top of thread	Engineering Forum

Posted by: CEstudent ® 05/28/2009, 01:56:23 Author Profile eMail author Edit

I think the formula you're looking for is (sigma) = My/I where y is the distance from the neutral axis of the beam, M is the applied moment, and I is the 2nd moment of area. This formula then implies that the normal stress due to bending is zero at the centroid of the cross section. The other formula for normal stress is (sigma) = P/A where P is the applied load and A is the cross-sectional area. A beam in pure bending has no transverse loading, and thus no shear stress. If there is a transverse loading, then the beam is not in pure bending and there is a shear. The shear produced by a transverse loading is (tau)= VQ/It where V is the load, Q is the first moment of area, and t is the thickness. I hope this helps....

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: : Shear stress due to bending
: : Shear stress due to bending -- CEstudent	Post Reply	Top of thread	Engineering Forum

Posted by: mohanjatinder ® 06/04/2009, 00:52:01 Author Profile eMail author Edit

I think their is some gap in understanding from what i had written earlier in my question. I mean to say that Formula Sigma=My/I is derived based on assuption that no shear stress is present in the beam. After derivation of this formula when we are driving the formula for shear stress their at one place we had used this formula of Sigma=My/I. Where as this formula is based on assuption that no shear stress is present in the beam. Then how can we use this formula for derivation of shear stress in a beam.

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