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Inclined Beam - Solving for Reaction forces
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Posted by: aimeceleste

12/15/2006, 14:02:58

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Imagine a beam at an incline, with a concentrated load at the halfway point along the beam.

The beam is pinned at the either end, with no other supports.

How do I solve for the reactions? I tried imagining it as a truss, but since it's not loaded at a joint, that falls apart quickly.

And I don't think that the vertical reactions are equal to half the load at the halfway point - if I try solving it that way, I get the horizontal reactions are zero, and that doesn't make sense. You would expect that there would be some horizontal component of the force due to the fact that the member is at an angle.

I am an engineering student, and I am pretty frustrated by an apparently simple problem.

Thanks for your help.








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Re: Inclined Beam - Solving for Reaction forces
Re: Inclined Beam - Solving for Reaction forces -- aimeceleste Post Reply Top of thread Forum
Posted by: stewart

12/20/2006, 17:19:48

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I'm not in the mood to think too hard, but I believe you have a two force member (reactions at each end are equal) pinned as it is. This should help close in on the variables vs equations.

Stewart







Modified by stewart at Wed, Dec 20, 2006, 17:23:01


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Re: Inclined Beam - Solving for Reaction forces
Re: Inclined Beam - Solving for Reaction forces -- aimeceleste Post Reply Top of thread Forum
Posted by: zekeman

12/16/2006, 15:06:16

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Hint:
First, try doing a problem where the load is axial. How many equations can you write? How many variables. Can't do it ? Indeterminate? Why?







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Re: Inclined Beam - Solving for Reaction forces
Re: Inclined Beam - Solving for Reaction forces -- aimeceleste Post Reply Top of thread Forum
Posted by: Kelly Bramble

12/16/2006, 08:07:26

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Solve it using vector techniques (for the applied load).







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Re: Re: Inclined Beam - Solving for Reaction forces
Re: Re: Inclined Beam - Solving for Reaction forces -- Kelly Bramble Post Reply Top of thread Forum
Posted by: swearingen

12/18/2006, 07:19:20

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Also, remember that if the supports are at the centerline of the beam (i.e., the centroid of the beam lies on a line that can be drawn between the supports), the vertical reactions at the ends will always be equal, no matter what the angle.







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