ONE THING MAKES ME STILL CONFUSING IF THE LIFT HEIGHT OF THE SCISSOR IS 3 METERS OR 5 METERS HOW MANY NOS OF CYLINDERS WILL BE NEEDED TO OPEN THE HYDRAULIC SCISSOR LIFT OF CAPACITY 500 KGS ?????
AND HOW THIS EQUATION F (FORCE ON THE CENTRE PIN) = (W + wf/2) / tan phi will play the role in this juncture ???
W = Weight of the load.
wf/2 = Weight of the frame.
Phi = Interior angle between horizontal and the arm.
Determine the maximum force at any angle of scisser lift operation your design will encounter.
Size hydraulic actuator(s) equal to or greater than that maximum operational force...
TYPING IN CAPS DOES NOT HELP COMMUNICATE!!!!