Electrical Equations ( Alternating Current ) AC

Instrumentation, Electrical, Control and Sensing Devices

Electrical circuits and alternating current AC equations anf formulae.

AC  Equations

DESIRED
DATA

ALTERNATING CURRENT

DIRECT
CURRENT

Single-Phase

Two-Phase*
Four-Wire

Three-Phase

Amperes when
kva is shown

kva x 1000
E

kva x 1000
2 x E

kva x 1000
1.73 x E
kva x 1000
E

Amperes when
kilowatts are shown

kw x 1000
E x pf
kw x 1000
2 x E x pf
  kw x 1000 
1.73 x E x pf
kw x 1000
E

Amperes when
horsepower is shown

  hp x 746  
E x %Eff x pf
    hp x 746    
2 x E x %Eff x pf
     hp x 746     
1.73 x E x %Eff x pf
hp x 746
E x %Eff

Kilovolt-Amperes

I x E
1000
I x E x 2
1000
I x E x 1.73
1000
I x E
1000

Kilowatts

I x E x pf
1000
I x E x 2 pf
1000
I x E x 1.73 x pf
1000
I x E
1000

Horsepower

I x E x %Eff x pf
746
I x E x 2 x %Eff x pf
746
I x E x 1.73 x %Eff x pf
746
I x E x %Eff
746
OHMS LAW
 Volts (E) = Amps (I) x Ohms (R)
Amps (I) = Volts (E) / Ohms (R)
Ohms (R) = Volts (E) / Amps (I)
 
R=Ohms, E=Volts, I=Amperes

POWER - AC CIRCUITS
Efficiency = 746 x Output HP / Input Watts
3 KW = Volts x Amps x PF x 1.732 / 1000
3 Amps = 746 x HP / 1.732 x Eff. x PF
3 Eff. = 746 x HP / 1.732 x Volts x Amps x PF
3 PF = Input Watts / Volts x Amps x 1.732
1 KW = Volts x Amps x PF / 1000
1 Amps = 746 x HP / Volts x Eff. x PF
1 Eff. = 746 x HP / Volts x Amps x PF
1 PF = Input Watts / Volts x Amps
HP (3) = Volts x Amps x 1.732 x Eff. x PF / 746
HP (1) = Volts x Amps x Eff. x PF / 746
1 KW = 1000 Watts
 
Eff. = Efficiency, PF = Power Factor
KW = Kilowatts
HP = Horsepower

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