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Electrical Equations ( Alternating Current ) AC
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Instrumentation, Electrical, Control and Sensing Devices
Product and Services Companies
AC Equations
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DESIRED DATA |
ALTERNATING CURRENT |
DIRECT CURRENT |
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Single-Phase |
Two-Phase* Four-Wire |
Three-Phase |
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Amperes when kva is shown |
kva x 1000 E |
kva x 1000 2 x E |
kva x 1000 1.73 x E |
kva x 1000 E |
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Amperes when kilowatts are shown |
kw x 1000 E x pf |
kw x 1000 2 x E x pf |
kw x 1000 1.73 x E x pf |
kw x 1000 E |
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Amperes when horsepower is shown |
hp x 746 E x %Eff x pf |
hp x 746 2 x E x %Eff x pf |
hp x 746 1.73 x E x %Eff x pf |
hp x 746 E x
%Eff |
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Kilovolt-Amperes |
I x E 1000 |
I x E x 2 1000 |
I x E x 1.73 1000 |
I x E 1000 |
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Kilowatts |
I x E x pf 1000 |
I x E x 2 pf 1000 |
I x E x 1.73 x pf 1000 |
I x E 1000 |
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Horsepower |
I x E x
%Eff x pf 746 |
I x E x 2 x
%Eff x pf 746 |
I x E x 1.73 x
%Eff x pf 746 |
I x E x
%Eff 746 |
- OHMS
LAW
- Volts
(E) = Amps (I) x Ohms (R)
- Amps
(I) = Volts (E) / Ohms (R)
- Ohms
(R) = Volts (E) / Amps (I)
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R=Ohms,
E=Volts, I=Amperes |
POWER - AC CIRCUITS
- Efficiency
= 746 x Output HP / Input Watts
- 3ø KW
= Volts x Amps x PF x 1.732 / 1000
- 3ø
Amps = 746 x HP / 1.732 x Eff. x PF
- 3ø Eff. = 746 x HP / 1.732 x Volts x Amps x PF
- 3ø PF
= Input Watts / Volts x Amps x 1.732
- 1ø KW
= Volts x Amps x PF / 1000
- 1ø
Amps = 746 x HP / Volts x Eff. x PF
- 1ø Eff. = 746 x HP / Volts x Amps x PF
- 1ø PF
= Input Watts / Volts x Amps
- HP (3ø)
= Volts x Amps x 1.732 x Eff. x PF / 746
- HP (1ø)
= Volts x Amps x Eff. x PF / 746
- 1 KW =
1000 Watts
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- Eff. =
Efficiency, PF = Power Factor
KW = Kilowatts
HP = Horsepower
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